Fabrication and Characterization of Anode-supported Solid Oxide Fuel Cell Based on Proton Conductor Electrolyte

Dan CAO; Mingyang ZHOU; Zhijun LIU; Xiaomin YAN; Jiang LIU

doi:10.15541/jim20190576

Journals >Journal of Inorganic Materials >Volume 35 >Issue 9 >Page 1047 > Article

Journal of Inorganic Materials
Vol. 35, Issue 9, 1047 (2020)

Fabrication and Characterization of Anode-supported Solid Oxide Fuel Cell Based on Proton Conductor Electrolyte

Dan CAO, Mingyang ZHOU, Zhijun LIU, Xiaomin YAN, and Jiang LIU^*

Author Affiliations

Guangzhou Key Laboratory for Surface Chemistry of Energy Materials, New Energy Research Institute, School of Environment and Energy, South China University of Technology, Guangzhou 510006, China

show less

DOI: 10.15541/jim20190576 Cite this Article

Dan CAO, Mingyang ZHOU, Zhijun LIU, Xiaomin YAN, Jiang LIU. Fabrication and Characterization of Anode-supported Solid Oxide Fuel Cell Based on Proton Conductor Electrolyte[J]. Journal of Inorganic Materials, 2020, 35(9): 1047 Copy Citation Text

show less

Abstract

Proton conducting oxide BaCe_0.7Zr_0.1Y_0.2O_3-_d (BCZY7) was synthesized by high temperature solid-state reaction method, which crystal structure and microstructure morphology were characterized. The anode-supported button solid oxide fuel cell (SOFC), NiO-BCZY7/BCZY7/La_0.6Sr_0.4Co_0.2Fe_0.8O_3-δ(LSCF)-BCZY7, was fabricated by combining the dip-coating and co-sintering processes. It operated by using H₂ (containing 3vol% H₂O) as fuel and ambient air as oxidant. The maximum power density of the cell reaches 203, 123 and 92 mW×cm^-2 at 600, 550 and 500 ℃, respectively. However, traditional SOFCs based on (ZrO₂)_0.92(Y₂O₃)_0.08 electrolyte usually display only tens of milliwatts output per unit area at 600 ℃. Proton conducting electrolyte greatly improves the low and medium temperature performance of SOFCs and provides a promising solution to reduce SOFCs’ operating temperature.

Keywords

activation energy proton conductor reduced temperature electrolyte solid oxide fuel cell

(2)${{\text{H}}_{2}}+1/2{{\text{O}}_{2}}={{\text{H}}_{2}}\text{O}$

View in Article

(3)E=$\frac{-{{\Delta }_{\text{r}}}{{G}^{\text{ }\!\!\theta\!\!\text{ }}}}{zF}-\frac{RT}{zF}\ln \frac{{{p}_{{{\text{H}}_{\text{2}}}\text{O}}}\text{/}{{p}^{0}}}{({{p}_{{{\text{H}}_{2}}}}\text{/}{{p}^{0}}){{({{p}_{\text{O}}}_{_{2}}\text{/}{{p}^{0}})}^{1/2}}}$